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Code
AI Hint
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Python
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def two_sum(nums, target):
for i in range(len(nums)):
for j in range(i + 1, len(nums)):
if nums[i] + nums[j] == target:
return [i, j]
return []
AI Mentor
Think about using a hash map to store the numbers you've seen so far. What would you store as the key and value?
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Blind 75 Master Sheet

The gold standard 75 problems that cover 90% of interview patterns in Arrays, Graphs, DP & Trees.

Distribution: 24 Easy · 44 Medium · 7 Hard
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🧠

Core DSA MasterclassFAANG Ready

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Beginner 15 min

Arrays & Memory Architecture

Contiguous RAM
const prefixSum = (arr) => arr.map((sum => v => sum += v)(0));
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Beginner 20 min

Two Pointers & In-Place Traversal

O(1) Space
let left = 0, right = arr.length - 1; while (left < right) ...
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Intermediate 25 min

Sliding Window & Substring Bounds

Subarrays
for (let r = 0; r < n; r++) { count.set(s[r], ...); while (invalid) ... }
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Intermediate 20 min

Binary Search on Value Spaces

O(log N)
let mid = left + Math.floor((right - left) / 2);
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LIVE CHECKPOINT • +25 XP

What is the time complexity of bisect_left() / lower_bound() on a sorted array of N elements?

Test your algorithmic intuition in real-time. Click an answer below to inspect the Socratic reasoning.

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The Socratic Difference

See how Guru guides you step-by-step on #1 Two Sum — without giving away the answer.

two_sum.py
#1. Two Sum (Easy)
1 class Solution:
2 def twoSum(self, nums, target):
3 seen = {}
4 for i, n in enumerate(nums):
5 diff = target - n
6 if diff in seen: return [seen[diff], i]
7 seen[n] = i
🧐

Hint #1: Gentle Nudge

Nudge

Think about what information you need to remember while iterating through `nums` so you don't need a nested O(n²) loop.

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